(x-8)(x+6)=x^2-4x-10

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Solution for (x-8)(x+6)=x^2-4x-10 equation:



(x-8)(x+6)=x^2-4x-10
We move all terms to the left:
(x-8)(x+6)-(x^2-4x-10)=0
We get rid of parentheses
-x^2+(x-8)(x+6)+4x+10=0
We multiply parentheses ..
-x^2+(+x^2+6x-8x-48)+4x+10=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+6x-8x-48)+4x+10=0
We get rid of parentheses
-1x^2+x^2+6x-8x+4x-48+10=0
We add all the numbers together, and all the variables
2x-38=0
We move all terms containing x to the left, all other terms to the right
2x=38
x=38/2
x=19

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